[eqn: f( theta)= {1} over {2} sin2 theta][eqn: image theta(차이` theta ^{3} 급)]

[eqn: g( theta)+S image2 TIMES {3} over {4} theta= {3} over {2} theta]

따라서 [eqn: lim _{theta`rarrow`0+} {{3f( theta)-2g( theta)} over {theta ^{2}}} = lim _{theta`rarrow`0+} {{2S} over {theta ^{2}}} =2]